设f(x)在[a,b]上连续,在(a,b)内二阶可导,且f(a)f(b)<0,f'(c)=0.a
设f(x)在[a,b]上连续,在(a,b)内二阶可导,且f(a)f(b)<0,f'(c)=0.a
设函数f(x)在[a,b]上连续,在(a,b)内有二阶导数,且有f(a)=f(b)=0,f(c)>0(a
设f(x)在[a,b]上连续,在(a,b)内可导,且f(a)=f(b)=0证明 存在c∈(a,b)使f‘(c)+f(c)
设f(x)在[a,b]上连续,在(a,b)可导,且f(a)=f(b)=0,证明存在c属于(a,b),使f'(c)+f(c
设f‘(x)在[a,b]上连续,且f(a)=0,证明:|∫b a f(x)dx|
设f(x)在[a,b]上连续,在(a,b)内可导,f(a)f(b)>0,f(a)f[(a+b)/2]0,f(a)f[(a
设函数f(x)在[a,b]上连续,在(a,b)可导,且f(a)*f(b)>0,f(a)*f((a+b)/2)
【中值定理证明题】设函数f(x)在[a,b]上连续,在(a,b)上可导,且f(a)f(b)>0,f(a)f((a+b)/
设f(x)在[a,b]上连续,在(a,b)内可导,且f(a)=f(b)=0.证明:在(a,b)内至少存在一点c,使f'(
设f(x)在(a,b)上连续,且f(a)=f(b),证明:存在点c属于(a,b)使得f(C)=f(c+b-a/2)
设f(x)在[a,b]上连续,在(a,b)内可导,且f(a)=f(b)=0
设函数f(x)在[a,b]上连续,在(a,b)内可导且f'(x)