英语翻译#includevoid transLate(char * from,char * to);int main()

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英语翻译
#include
void transLate(char * from,char * to);
int main()
{
char num[20];
char eng[11][10]={"zero","two","three","four","five","six","seven","eight","nine","ten"};
int i;
printf("please enter a string of number:");
gets(num);
for(i=0;num[i]!='\0';i++)
{
transLate(num,eng);
printf("、");
}
printf("\n");
return 0;
}
void transLate(char * from,char * to)
{
\x09printf("%s",to[from-'1']);
}

void transLate(char * from,char * to)
{
printf("%s",to[from-'1']);
}
整个函数是错的
传入的第二个参数应该是char**to
第一个参数char*from没有转换成int类型,不可以这样使用,会造成segmentation fault

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