α为第三象限角 f(α)=Sin(π+αCos(2π-α)/tan(π-α)Sin3/2π-α) 1、化简f(α)2、若
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α为第三象限角 f(α)=Sin(π+αCos(2π-α)/tan(π-α)Sin3/2π-α) 1、化简f(α)2、若Cos(α-3/2π)=1/5 3、α=-1380°,求f(α)
是Sin(π+α)Cos(2π-α)/tan(π-α)Sin3/2π-α)
1、
Sin(π+α) = -Sinα
Cos(2π-α) = Cosα
tan(π-α) = -tanα =-sinα/cosα
Sin3/2π-α) = -cosα
∴ f(α)= - cosα
2、
Cos(α-3/2π)=1/5 = -Sinα
由cos^2 α +sin^2 α =1得
cos α = -2√6 /5
f(α)= - cosα = 2√6 /5
3、
α=-1380°
f(α)= - cosα =-cos1380 ° = -cos60° =-1/2
1、
Sin(π+α) = -Sinα
Cos(2π-α) = Cosα
tan(π-α) = -tanα =-sinα/cosα
Sin3/2π-α) = -cosα
∴ f(α)= - cosα
2、
Cos(α-3/2π)=1/5 = -Sinα
由cos^2 α +sin^2 α =1得
cos α = -2√6 /5
f(α)= - cosα = 2√6 /5
3、
α=-1380°
f(α)= - cosα =-cos1380 ° = -cos60° =-1/2
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