char p[20]={'a','b','c','d'},q[]="abc",r[]="abcde"; strcat(p
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char p[20]={'a','b','c','d'},q[]="abc",r[]="abcde"; strcat(p,r);strcpy(p+st
char p[20]={'a','b','c','d'},q[]="abc",r[]="abcde";
\x09strcat(p,r);strcpy(p+strlen(q),q);
\x09printf("%d\n",strlen(p));
怎么运行,结果为什么是6
char p[20]={'a','b','c','d'},q[]="abc",r[]="abcde";
\x09strcat(p,r);strcpy(p+strlen(q),q);
\x09printf("%d\n",strlen(p));
怎么运行,结果为什么是6
strcat(p,r);后
p="abcdabcde"
strcpy(p+strlen(q),q);后p的第7位是'\0'
p="abcabc"
当然是6
p="abcdabcde"
strcpy(p+strlen(q),q);后p的第7位是'\0'
p="abcabc"
当然是6
char p[20]={'a','b','c','d'},q[]="abc",r[]="abcde"; strcat(p
mian {char p[20]={'a','b','c','d'},q[]="abc",r[]="abcde"; st
char p[]={'a','b','c'},q[]="abc";
#include #include main() { char p[20]={'a','b','c','d'},q[]=
main() { char a[]={'a','b','c','d'}; char *p=(char *)(&a+1);
char p[]={'a','b','c'}与q[]="abc";的区别
main(){ char *p,*q; p=(char*)malloc(sizeof(char)*20);q=p; sc
#include; char *p="ABC" printf("%d",strlen(p)+*p);
char point(char*p) {p+=3;return *P} main() {char b[4]={'a','
char a[80]="ABC",b[80]="LMNP"; int i=0; strcat(a,b); while(a
设:char a[]="abc",b[]="xyz";则表达式strcat(a,b))的值是
已知: char a[]=”abcde”,*p; 表达式 *(p+5)的值 为?