{int **k,*k,b=100; a=&b;k=&a;printf("%d\n",**k);} 输出结果.
{int **k,*k,b=100; a=&b;k=&a;printf("%d\n",**k);} 输出结果.
printf("k=% %d\n",结果呢?
main( ) {int k=4,a=3,b=2,c=1;printf ("%d\n",k<a
以下程序的运行结果是.main(){int k=4,a=3,b=2,c=1;printf(“%d\n”,k
、下面程序的输出是( ).main() { int k=13; printf(“k=%d,k=%o,k=%x\n”,k,
int k=2; while(k==0) printf("%d",k); k--; printf("\n");下列循环的
main() { int i,b,k=0; for(i=1;i=0) k++; } printf("%d,%d",k,b
main() {int i,b,k=0; for(i=1;i=0) k++;} printf("%d,%d",k,b);
#include void main() { int k=-1; printf("%d,%u\n",k,k); }
fun(int k) {if(k>0)fun(k-1) printf("%d",k); } main() {int w=
下面的程序的输出结果是() main(){int k=11;printf (''k=%d,k=%0,k=%x\n'');
{int n=2,k=0; while(k++&&n++>2); printf("%d %d\n",k,n);为什么答案