76x-66y=4082

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根据x+x+x+y+y=54,x+x+y+y+y=56,求出x.y的值

x+x+x+y+y=54,x+x+y+y+y=56得出3X+2Y=54,2X+3Y=56扩大后得出6X+4Y=108,6X+9Y=118两式相减得出Y=2得出X=50/3

(x+y-z)(x-y+z)=

[x+(z-y)][x-(z-y)]=x-(z-y)记得采纳啊

(x-y)(x+y)(xx-yy)=?

(x-y)(x+y)(xx-yy)=(x^2-y^2)(x^2-y^2)=x^4-2x^2y^2+y^4

因式分解下列式子:x(x-y)+y(y-x)=?

x(x-y)+y(y-x)=x(x-y)-y(x-y)=(x-y)(x-y)=(x-y)²明教为您解答,请点击[满意答案];如若您有不满意之处,请指出,我一定改正!希望还您一个正确答复!祝您

y'-2y=(e^x)-x

首先求齐次方程通y'-2y=0特征方程:x-2=0x=2为特征根∴y=Ce^(2x)设方程的一个特解为y=Ae^x+ax+b代入方程:Ae^x+a-2Ae^x-2ax-2b=-Ae^x-2ax+a-2

(x*x+y*y)(x*x+y*y)-(x*x+y*y)=12 求x*x+y*y等于多少

令a=x²+y²则a²-a=12a²-a-12=0(a-4)(a+3)=0a=4,a=-3平方数大于等于0所以a=-3不成立所以x²+y²=

x+x+x+y=52 y+y+y+x=36求x

x+x+x+y+y+y+y+x=52+364(x+y)=88x+y=22x+x+x+y=522x+22=522x=30x=15y=22-xy=22-15y=7

x+y=5; x^y+y^x=17

X=2,Y=3或X=3,Y=2

已知x、y均为实数,且满足xy+x+y=17,x^2y+y^2x=66,求x^4+x^3y+x^2*y^2+y^3x+y

由已知:xy+x+y=17,xy(x+y)=66,可知xy和x+y是方程t2-17t+66=0的两个实数根,得:t1=6,t2=11.即xy=6,x+y=11,或xy=11,x+y=6.当xy=6,x

求y'=y/(y-x)

∵令y=xt,则y'=xt'+t代入原方程,得xt'+t=t/(t-1)==>xt'=(2t-t^2)/(t-1)==>(t-1)dt/(2t-t^2)=dx/x==>2dx/x+[1/t+1/(t-

已知X-Y/X+Y=3,求代数式2(x-y)/X+Y-3X+Y/X+Y

X+Y分之X-Y等于3x=-2yX+Y分之2(x-y)减X+Y分之3X+Y=(-x-3y)/(x+y)=1

已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)

因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6

解方程组:2/(x+y)+5/(x-y)=18 9/(x+y)-10/(y-x)=66

2/(x+y)+5/(x-y)=189/(x+y)-10/(y-x)=66设x+y=a,x-y=b,原方程化为2/a+5/b=18-----1(1)9/a+10/b=66-------(2)(2)-(

[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013

先一个一个的展开括号项,再同项合并就行了啊[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x=[xx-xy-(xy-yy)+x(x-y)+y(x-y)]÷2x=[xx-xy-xy+yy+xx-

解方程组:2/(x+y)+5/(x-y)=18 9/(x+y)-10/(y-x)=66

另a=1/(x+y),b=1/(x-y);则2a+5b=18;9a+10b=66;解得a=6,b=6/5;即       &nbs

1.2x+2y=76(x+y)-4x=332.关于x、y的方程组 x+y=3,x-y=1 x-my=2 与 nx-y=2

1、2x+2y=7(1)6(x+y)-4x=33化简得2x+6y=33(2)(2)-(1),得4y=26∴y=6.5代入(1)得x=-32、x+y=3x-y=1解得x=2,y=1代入x-my=2与nx

f(x,y,z,w)=x*(x+y)*(x+y+z)*(x+y+z+w)

f=x+1f+u=2x+3f+u+c=3x+8f+u+c+k=4x+15f(f,u,c,k)=(x+1)(2x+3)(3x+8)(4x+15)

二元函数f(x,y)=x+y/x-y,求f(y/x,x/y)

假设:X=Y/XY=X/Y带入函数就是:F(y/x,x/y)=(y/x+x/y)/(y/x—x/y)=x²+y²)/(y²-x²)希望可以帮助你!

) y=cos(x-y)

1.两边求导得:y'=-sin(x-y)(1-y')解得y'=sin(x-y)/[sin(x-y)-1]2.y'=-e^-xy''=e^-xy'"=-e^-x3.y'"=(e^2x)'"(sinx)+