(1/2003-1)(1/2002-1)(1/2001-1)...*(1/1001-1)(1/1000-1)
(1/2003-1)(1/2002-1)(1/2001-1)...*(1/1001-1)(1/1000-1)
(2003/1-1)×(2002/1-1)×(2001/1-1)×.×(1001/1-1)×(1000/1-1)=?
(1/2004 -1)(1/2003 -1)(1/2002 -1).(1/1001 -1)(1/1000 -1)
求:(1/2003-1)(1/2002-1)(1/2001-1)(1/2000-1)(1/1999-1)…(1/1001
|1/2004-1/2003|+|1/2003-1/2002|+|1/2002-1/2001|+|1/2001-1/20
化简:|1/2004-1/2003|+|1/2003-1/2002|+|1/2002-1/2001|-|1/2001-1
(1/2003-1) (1/2002-1) (1/2001-1).(1/1000-1)
写过程(1/2004-1) (1/2003-1) (1/2002-1)...(1/1001-1) (1/1000-1)=
(2002+2003*2001)/(2002*2003-1)简算
1/1999×2000+1/2000×2001+1/2001×2002+1/2002×2003+1/2003×2004+
(2003/1-1)(2002/1-1)(2001/1-1)(2000/1-1)(1999/1-1)...(1001/1
(1/2003—1)×(1/2002—1)×(1/2001—1)×...(1/1000—1)