y=x^2+10x+16 and Y= 2x+4

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y=x^2+10x+16 and Y= 2x+4
x^2+y^2=5 y=3x-1

y=x^2+10x+16 and Y= 2x+4
x^2+10x+16 = 2x+4
x^2+8x+12 = 0
(x+2)(x+6)=0
x1=-2,y1=0
x2=-6,y2=-8
x^2+y^2=5 y=3x-1
x^2+(3x-1)^2=5
x^2+9x^2-6x+1=5
5x^2-3x-2=0
(x-1)(5x+2)=0
x1=1,y1=2
x2=-2/5,y2=-11/5

已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y 解方程组 10（x-y)=3(x+y)+15 6(x+y)=4(2x-y)+16 数学题x-y=2 and x二次+y二次=16,求x. (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai [x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013 {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20 {(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20 3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27 4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6 已知4x=9y求(1)x+y/y (2)y-x/2x (x+y)(x+2y)(x+3y)(x+4y)=-40