作业帮matlab代入方程求解
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matlab代入方程求解
已知F1=0.3320X1+0.2741X2+0.3294X3+0.3309X4+0.0835X5+0.3321X6+0.3284X7+0.2561X8+0.3311X9+0.3042X10+0.3220X11
矩阵为a=[-1.3330 -0.9860 -1.5887 -1.2713 -0.8769 -1.3147 -1.2302 -2.0612 -1.4625 -1.5292 -1.2887;
-1.1132 -0.0999 -1.0157 -1.1315 -1.2947 -0.9427 -0.8872 0.3740 -0.8494 -1.3438 -0.8928;
-0.2847 -0.7062 -0.1152 -0.3183 1.3084 -0.5157 -0.5380 -0.1739 -0.5528 0.2356 -0.5740;
0.0118 -0.6712 0.0993 -0.0049 0.8907 -0.0229 -0.1523 0.3131 0.1196 0.5097 0.0065;
0.4327 -0.2865 0.5809 0.4006 0.4407 0.4033 0.3243 -0.1131 0.4624 0.5754 0.6413;
0.9177 1.0543 0.9739 0.8999 0.3765 0.9831 0.9273 1.0436 1.1282 0.7298 0.5153;
1.3687 1.6956 1.0656 1.4254 -0.8448 1.4097 1.5562 0.6175 1.1546 0.8225 1.5924];
如何编写matlab程序代入原方程求出F1的值?
已知F1=0.3320X1+0.2741X2+0.3294X3+0.3309X4+0.0835X5+0.3321X6+0.3284X7+0.2561X8+0.3311X9+0.3042X10+0.3220X11
矩阵为a=[-1.3330 -0.9860 -1.5887 -1.2713 -0.8769 -1.3147 -1.2302 -2.0612 -1.4625 -1.5292 -1.2887;
-1.1132 -0.0999 -1.0157 -1.1315 -1.2947 -0.9427 -0.8872 0.3740 -0.8494 -1.3438 -0.8928;
-0.2847 -0.7062 -0.1152 -0.3183 1.3084 -0.5157 -0.5380 -0.1739 -0.5528 0.2356 -0.5740;
0.0118 -0.6712 0.0993 -0.0049 0.8907 -0.0229 -0.1523 0.3131 0.1196 0.5097 0.0065;
0.4327 -0.2865 0.5809 0.4006 0.4407 0.4033 0.3243 -0.1131 0.4624 0.5754 0.6413;
0.9177 1.0543 0.9739 0.8999 0.3765 0.9831 0.9273 1.0436 1.1282 0.7298 0.5153;
1.3687 1.6956 1.0656 1.4254 -0.8448 1.4097 1.5562 0.6175 1.1546 0.8225 1.5924];
如何编写matlab程序代入原方程求出F1的值?
a=[-1.3330 -0.9860 -1.5887 -1.2713 -0.8769 -1.3147 -1.2302 -2.0612 -1.4625 -1.5292 -1.2887;
-1.1132 -0.0999 -1.0157 -1.1315 -1.2947 -0.9427 -0.8872 0.3740 -0.8494 -1.3438 -0.8928;
-0.2847 -0.7062 -0.1152 -0.3183 1.3084 -0.5157 -0.5380 -0.1739 -0.5528 0.2356 -0.5740;
0.0118 -0.6712 0.0993 -0.0049 0.8907 -0.0229 -0.1523 0.3131 0.1196 0.5097 0.0065;
0.4327 -0.2865 0.5809 0.4006 0.4407 0.4033 0.3243 -0.1131 0.4624 0.5754 0.6413;
0.9177 1.0543 0.9739 0.8999 0.3765 0.9831 0.9273 1.0436 1.1282 0.7298 0.5153;
1.3687 1.6956 1.0656 1.4254 -0.8448 1.4097 1.5562 0.6175 1.1546 0.8225 1.5924];
x1=a(:,1);
x2=a(:,2);
x3=a(:,3);
x4=a(:,4);
x5=a(:,5);
x6=a(:,6);
x7=a(:,7);
x8=a(:,8);
x9=a(:,9);
x10=a(:,10);
x11=a(:,11);
f1=0.33201*x1+0.2741*x2+0.3294*x3+0.3309*x4+0.0835*x5+0.3321*x6+0.3284*x7+0.2561*x8+0.3311*x9+0.3042*x10+0.3220*x11
-1.1132 -0.0999 -1.0157 -1.1315 -1.2947 -0.9427 -0.8872 0.3740 -0.8494 -1.3438 -0.8928;
-0.2847 -0.7062 -0.1152 -0.3183 1.3084 -0.5157 -0.5380 -0.1739 -0.5528 0.2356 -0.5740;
0.0118 -0.6712 0.0993 -0.0049 0.8907 -0.0229 -0.1523 0.3131 0.1196 0.5097 0.0065;
0.4327 -0.2865 0.5809 0.4006 0.4407 0.4033 0.3243 -0.1131 0.4624 0.5754 0.6413;
0.9177 1.0543 0.9739 0.8999 0.3765 0.9831 0.9273 1.0436 1.1282 0.7298 0.5153;
1.3687 1.6956 1.0656 1.4254 -0.8448 1.4097 1.5562 0.6175 1.1546 0.8225 1.5924];
x1=a(:,1);
x2=a(:,2);
x3=a(:,3);
x4=a(:,4);
x5=a(:,5);
x6=a(:,6);
x7=a(:,7);
x8=a(:,8);
x9=a(:,9);
x10=a(:,10);
x11=a(:,11);
f1=0.33201*x1+0.2741*x2+0.3294*x3+0.3309*x4+0.0835*x5+0.3321*x6+0.3284*x7+0.2561*x8+0.3311*x9+0.3042*x10+0.3220*x11