(1) 2x²-3x=0 (2)(3y+5)²=4y²
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
(1)已知x+y=6,x²-y²=5,求x-y的值(2)若x+y=3,x²+y²
2x²-3xy=y²=0(x,y不得o)求x/y+y/x
已知x²+|y+x|=x-1/4,求(3x+y)²(2x-y)²-(4x²+y&
(3x-y)²-2x(4x-5y)-(x+2y)²
(x+y)-(x+y)平方 因式分解 解方程 2x²=3x (3x-1)² - 4=0 5x-15x
若|x+y-1|+(x-y-2)²=0,求代数式(x+2y)(x-2y)-(2x-y)(-y-2x)的值.
先化简再求值 :[(x+2y)²-(x+y)(3x-y)-5y²]÷(2x),其中x=—2,y=5
已知4x²+y²-4x-6y+10=0求(2/3x(√9x)+(y²√x/y³)
已知|x+y+2|+(2x-3y-1)²=0 求 ⑴x、y的值 ⑵2x³-x²-3y
已知x-y=1,y≠0,求{(x+2y)²+(2x+y)(x+4y)-3(x+y)(x-y)}÷y的值.
已知x²-4x-1=0,求代数式(2x-3)²-(x+y)(x-y)-y²的值