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3(x-1)³y-(1-x)³z m(x-y)²-x+y x²(x+y)(y-x

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3(x-1)³y-(1-x)³z m(x-y)²-x+y x²(x+y)(y-x)-xy(x+y)(x-y) 因式分解
3个式子吧?
3(x-1)³y-(1-x)³z
=3(x-1)³y+(x-1)³z
=(x-1)³(3y+z)
(2)
m(x-y)²-x+y
=m(x-y)²-(x-y)
=(x-y)[m(x-y)-1]
=(x-y)(mx-my-1)
(3)
x²(x+y)(y-x)-xy(x+y)(x-y)
=x²(x+y)(y-x)+xy(x+y)(y-x)
=x(x+y)(y-x)(x+y)
=x(x+y)²(y-x)