r=a(1 cosx)
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S=(1/2)∫(0->2π)(r^2)dθ=(1/2)∫(0->2π)[a^2(1-cosθ)^2]dθ=(3πa^2)/2
(1)当x=π4时,向量a+b=(22,1)+(22,1)=(2,2).(2)∵a+b=(sinx+cosx,2),∴f(x)=(sinx+cosx)2+4+m=sin2x+5+m.∵函数f(x)为奇
f(x)=a*b-1=(根号3*sin2x+2cos^2x-1=2sin(2x+π/6)(1)有b^2=ac令a=kb则c=b/kcosB=(a^2+c^2-b^2)/(2ac)=(k^2+1/k^2
对于剩下的部分就是圆r=3cosθ,从π/3积分到π/2,仍然上下对称S2=9总面积S=S1+S2=3π/4-9根号3/8+π/2+9根号3/8=5π/4θ
(1)函数f(x)=a·β=√3sin2x+(sinx+cosx)(sinx-cosx)=√3sin2x-(cos²x-sin²x)=√3sin2x-cos2x=2sin(2x-π
首先求出f(x)的表达式.f(x)=|a|^2+a·b=1+sinx·cosx+cosx·cosx=1+1/2*sin2x+1/2*(1+cos2x)=3/2+√2/2*sin(2x+π/4)所以,最
1.f(x)=2sinxcosx+cos^2(x)-sin^2(x)=sin2x+cos2x=根2倍sin(2x+π/4)2x+π/4=2kπ+π/2(k∈Z)时sin(2x+π/4)取得最大值根2即
因a+b=(2,0),所以sinx+cosx=0得sinxcosx=0得出sin^2x+2sinxcosx=4sinxcosx=0(2)因a-b=(0,1/5),得sinx-cosx=1/5得出sin
f(x)=ab=2(cosx)^2+2√3sinxcosx=4cosxsin(x+30)g(x)=4cox(x+π/6)sin(x+π/3)-1g'(x)=4sin(x+π/6)sin(x+π/3)+
x=0:.001:2*pi; rho=3*(1+cos(x));polar(x,rho,'r') 再问:能不能给我个平面直角坐标系的图大哥我
x是角度吧?是条心性线,要用定积分,从0积分到2π.∫r*rdx=∫(a+aCosx)*(a+aCosx)dx=a*a∫dx+2a*a∫Cosxdx+a*a∫CosxCosxdx=2aaπ+0+aaπ
f(x)=2cos^2x+√3sin2x=1+cos2x+√3sin2x=2sin(2x+π/6)+1(1)若f(x)=0,sin(2x+π/6)=-1/2x∈(-π/2,0),x=-π/62x=-π
若a\\b即要证(4cosx+√3)*sinx-cosx=0.当x=10°(4cosx+√3)*sinx-cosx=2sin2x+√3*sinx-cosx=2sin2x+2sin(x-π/6)=2si
1.ab=2cos^2x+√3*sin2x=cos2x+√3sin2x+1=2*sin(2x+π/6)+1.若f(x)=1-√3且x∈[-π/3,π/3],则有1-√3=2*sin(2x+π/6)+1
(1)a*b=cosx(√3sinx+cosx)-y=√3sinxcosx+cos²x-y=√3/2*sin2x+1/2*(1+cos2x)-y=√3/2*sin2x+1/2*cos2x+1
解f(x)=-cos²x+sinxcosx+1=1/2(2sinxcosx)-1/2(2cos²x-1)+1/2=1/2sin2x-1/2cos2x+1/2=√2/2(√2/2si
①2a=(2倍根号3sinx,2cosx)2a·b=2倍根号3sinxcosx+2cosxcosx=根号3sin2x+cos2x+1经过合一变形之后得.2sin(2x+π/6)+1f(x)=2sin(
(1)向量a=(2cosx,1),b=(cosx,根号3sin2x),f(x)=向量a*向量b=2cos²x+√3sin2x=√3sin2x+cos2x+1=2sin(2x+π/6)+1∵f
f(x)=a(a-b)=(sinx,cosx)*(sinx-cosx,0)=sin²x-sinxcosx=1/2*(1-cos2x)-1/2*sin2x.正弦余弦二倍角公式=-1/2*(si