c语言递归函数实现fibonacci数列的输出,输出其前28项

#include#defineN20main(){intf(intn);inti;for(i=1;i

#include"stdio.h"#include"stdlib.h"#include"string.h"#definenull0structnode{chardata;structnode*lchi

#include#defineCOL10//一行输出10个longscan(){//输入求fibonacci函数的第N项intn;printf("InputtheN=");scanf("%d",&n)

你学过数据结构了吗?如果学过,那就比较好理解,该算法的思路和求二叉树的高度的算法的思路是十分类似的.把取这i个物体看成i个阶段,则该二叉树有i+1层.其中空背包时为根结点,左孩子则为放弃了第1个物品后

#includeusingnamespacestd;doublepnx(int,double);intmain(){doublen,x;coutx;cout再问：谢谢能加个好友吗给个q也行以后请多指教

好的我帮你你分析以下你的程序：1调用是age(5)它再调用age(4),然后返回age(4)+22age(4)过程中调用age(3),然后返回age(3)+23在age(3)过程中调用age(2),然

#include#includeintjiecheng(inte,intn){//intx=e;if(n==1)returne;else{returne*jiecheng(e,--n);}}intma

#includeinttest(inttotal,intcount){if(count==6)//如果分五次之后仍满足要求,则该数为所求{return1;}if(total%5!=1)//如果不满足分

voidprt(intn){printf("%d",n%10);if(n>10)prt(n/10);}intmain(void){inta;printf("请输入整数：");scanf("%d"

#includeintf(inti){intsum=i;if(i>0)sum+=f(i-2);returnsum;}intF(inti){intsum=i;if(i>0)sum+=f(i-2

#include <stdio.h>char* dg(char* instr, char* outstr, char* 

intFibona(intn){intm;if(n==1)return(1);elseif(n==2)return(1);else{m=Fibona(n-1)+Fibona(n-2);return(m

#includelongfib(intn){inta;if(n==1)a=1;elseif(n==2)a=1;elsea=fib(n-1)+fib(n-2);returna;}voidmain(){\

longmi(intx,intn){if(n=1)returnn;elsereturn((long)x*mi(x,n-1);}

First,youcansolveitlikethis:#includeusingnamespacestd;voidprintArray1(data_tarray[],size_tsize){for(

1.#include"stdio.h"//#defineRECURSION1#ifdefRECURSIONlongfact(intn){if(n

#include#includeintmain(intargc,char*argv[]){intm,n,c,i,j,max;scanf("%d%d",&m,&n);if(m=2){printf("Th

递归函数如下：首先斐波拉楔数列的前n项和递推公式为S（n）=S（n-1）+S（n-2）+1；(根据通项公式a[n]=a[n-1]+a[n-2]很容易推导出来)递归函数如下所示;intsum_Fibon

#include#includefun(intx);intmain(void){char*pszBuff=NULL;inta;inti=1;intsumResult=0;printf("inputai

intN(intx){if(x==0){return1;}else{returnx*N(x-1)}}intiRet=0;for(inti=1;i