完全平方公式3X减2Y+3Z
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/29 15:53:54
1.运用平方差公式,原式=(3x-5+2x+7)(3x-5-2x-7)=(5x+2)(x-12)=5x的平方-58x-242.原式=(x的平方-4)的平方=x的4次方-8x的平方+163.原式=[2x
(x+y-2)(x+y+3)=[(x+y)-2][(x+y)+3]=(x+y)^2+(3-2)(x+y)-6=(x+y)^2+(x+y)-6=x^2+2xy+y^2+x+y-6(2x+y-3)(2x-
(x+2y-3z)^2=x^2+(2y)^2+(--3z)^2+2*x*(2y)+2*x*(--3z)+2*(2y)*(--3z)=x^2+4y^2+9z^2+4xy--6xz--12yz.(2x--
原式=4x²-12xy+9y²-(16y²-9x²)=4x²-12xy+9y²-16y²+9x²=13x²-1
(2x+y+1)(2x-y-1)=[2x+(y+1)][2x-(y+1)]=(2x)^2-(y+1)^2=4x^2-y^2-2y-1(3x-y-1)^2=[3x-(y+1)]^2=(3x)^2-2*3
(2x+y-3)^2=((2x+y)-3)^2=(2x+y)^2-6(2x+y)+9=4x²+4xy+y²-12xy-6y+9=4x²-8xy+y²-6y+9
(x+2y-3z)(x-2y+3z)+(2y-3x)的平方=[x+(2y-3z)][x-(2y-2z)]+(2y-3z)^2=x^2-(2y-3z)^2-(2y-3z)^2=x^2
(x-2y+3z)^2-(x+2y-3z)^2=[x-2y+3z+(x+2y-3z)][x-2y+3z-(x+2y-3z)]=2x*(-4y+6z)=-8xy+12xz
(x+3y-z)(-x+3y+z)=[3y+(x-z)][3y-(x-z)]=9y²-(x-z)²=9y²-(x²-2xz+z²)=9y²-
(2x+3y-z)(2x-3y+z)=[2x+(3y-z)][(2x-(3y-z)]=4x^2-(3y-z)^2=4x^2-(9y^2-6yz+z^2)=4x^2-9y^2+6yz-z^2
(3x+2y)(3x-2y)+(-3x-2y)^2=(3x+2y)(3x-2y)+(3x+2y)^2=(3x+2y)(3x-2y+3x+2y)=6x(3x+2y)=18x^2+12xy
原式=(1/3)^2-2*2y*1/3+4y的平方=1/9的平方-4/3y+4y的平方
不能,把它看成对y的二次多项式就容易看出来再问:什么意思?说详细点再答:就是变成y^2+2x^2*y+x^3再问:原题就是这个式子再答:我的意思是你变成这个方向就是把y作为主元素那么要分解肯定是(y+
(x+3y)^2+(x-3y)^2=2(x^2+9y^2)2(x^2+9y^2)+2(x^4-y^4)=2(x^4+x^2+9y^2-y^4)
(x-y+z)的平方-(x+y-z)的平方=(x-y+z+x+y-z)(x-y+z-x-y+z)=2x×(-2y+2z)=4xz-4xy
(2x-3y)²=4x²-12xy+9y²(-x-y)²=x²+2xy+y²如果本题有什么不明白可以追问,
(x+y+z)²=[(x+y)+z]²=(x+y)²+z²+2(x+y)z=x²+y²+z²+2xy+2yz+2zx
(-4x+3y)²=(-4x)²-2×4x×3y+(3y)²=16x²-24xy+9y²
1.12x+4+12xy-4y*y3.x*x-(y-z)*(y-z)
原式=4x²-12xy+9y²-9y²+4x²=8x²-12xy