化简x-2分之根号x-2除以根号x³-2x²分之x-搜答案-拍题作业网

原式=[(x+1)/x]÷[(2x²/2x)-(x²+1)/2x]=[(x+1)/x]÷[(2x²-x²-1)/2x]=[(x+1)/x]×[2x/(x&sup

不知道能不能看见,结果是（6根号2）X

[x的平方-x分之x+1-x的平方-2x+1分之x]除以x分之1=[(x+1)/x(x-1)-x/(x-1)²]×x=(x+1)/(x-1)-x²/(x-1)²=(x&#

x+2分之x-x+2分之x平方+2x+1除以x-1分之x平方-1=[x/(x+2)-(x²+2x+1)/(x+2)]÷(x²-1)/(x-1)=[(x-x²-2x-1)/

=x/(x-1)-x/(x+1)×(1-x)/2x=x/(x-1)+(x-1)/2(x+1)=[2x(x+1)+(x-1)²]/2(x-1)(x+1)=(3x²+1)/2(x

(x-1分之x平方-1-x分之2x)除以x-1分之x,其中x=根号3+1=[x²/(x-1)+2x/(x-1)]÷x/(x-1)=x(x+2)/(x-1)*(x-1)/x=x+2其中x=根号

原式=[√(x/4)-2x√(1/x)]÷3√x=√(x/4)÷3√x-2x√(1/x)÷3√x=(1÷3)×√(x/4÷x)-(2x÷3)×√(1/x÷x)=1/3×√(1/4)-(2x/3)×√(

把平方代入根号除以根号得出｛3根号X-2根号X｝除以3根号X=根号X除以3根号X=3分之1

√x-√(x-2)/(x-2)÷√[x/(x^3-2x^2)]=√x-1/√(x-2)÷1/√(x^2-2x)=√x-1/√(x-2)乘√(x^2-2x)=√x-1/√(x-2)乘√[x(x-2)]=

=根号16X6x^3/4xX3=根号4X6X3x^2=根号72x^2=6x根号2

-8xy√2x

原式=1÷2×√[xy/(y²/x)]=1/2×√(x²y/y²)=x√y/(2y)

x=√3/3(x-3)/(x+3)=(√3-9)/(√3+9)=(√3-9)^2/(-78)=(18√3-84)/78=(6√3-28)/27[(x^2-3x)/(x-2)]/[(x+3)/(2-x)

规范而详细解答过程看图,明白就采纳,祝马年学习进步

因为(x-1/x)÷（x+1）/x=（x+1）（x-1)/x×x/（x+1）=x-1.所以当x=根2+1时,原式=根2..

直接带入算再问：必须要过程的，再答：见图

原式=（3/2根2x-根2x+4根2x)÷3根2x=9/2根2x÷3根2x=3/2...

可知x≥0,y≥0(x-y)/(√x+√y)-(x-2√xy+y)/(√x-√y)=(√x+√y)(√x-√y)/(√x+√y)-(√x-√y)²/(√x-√y)=(√x-√y)-(√x-√

根号2x乘以根号y分之x乘以（根号x分之y除以根号y分之一）=根号2x^2/y*（根号y/x*根号y）=根号2x^2/y*根号y^2/x=根号2x/y再代入x、y的值就可以了.

答：[(x-2)/(x-1)]÷[x+1-3/(x-1)]=[(x-2)/(x-1)]÷[(x²-1-3)/(x-1)]=[(x-2)/(x-1)]×(x-1)/(x²-4)=1/