(1)已知x+y=14,xy=-12,求(x-y)^2的值 (2)(2^2+1)(2^4+1)(2^8+1)(2^16+
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(1)已知x+y=14,xy=-12,求(x-y)^2的值 (2)(2^2+1)(2^4+1)(2^8+1)(2^16+1)-1
(1) (x-y)^2=(x+y)^2-4xy=14^2-4*(-12)= 204 (2) (2^2+1)(2^4+1)(2^8+1)(2^16+1)-1 =(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)/(2^2-1)-1 =(2^4-1)(2^4+1)(2^8+1)(2^16+1)/(2^2-1)-1 =.=(2^32-1)/(2^2-1)-1 =(2^32-4)/3
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