1-tan*2x/1+tan*2x=cos*2x-sinx
化简sin^4x/sinx-cosx - (sinx+cosx)cos^2x/tan^2x-1
tan(3x/2)-tan(x/2)-2sinx/(cosx+cos(2x))=?
化简tan(3x/2)-tan(x/2)-sinx/(cos(3x/2)*cos(x/2))
证明1-tan^2x/1+tan^2x=cos^2x-sin^2x
证明(1-2sin x cos x )/(cos^2x-sin^2x)=(1-tan x)/(1+tan x)
(sin^x/sinx-cosx)-sinx+cosx/tan^2x-1
(2sinx*cosx)/sin^2x+cos^2x=(2tanx)/tan^2x+1 怎么推导的?
求证 sin^2x/(sinx-cosx)-(sinx+cosx)/tan^2 x-1=sinx+cosx
1-cosX/sinX=tan(X/2) 请问怎么证明,
帮忙证明tan(x/2)=(1-sinx)/cosx
证明:tan(x/2)=sinx/1+cosx
请问为什么(1-sinx)/cosx = tan(x/2)?