计算∫(π,0)根号sinx-sin^3xdx
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计算∫(π,0)根号sinx-sin^3xdx
∫[0--->π]√(sinx-sin³x)dx
=∫[0--->π]√[sinx(1-sin²x)]dx
=∫[0--->π]√[sinxcos²x]dx
=∫[0--->π/2] cosx√(sinx)dx-∫[π/2--->π] cosx√sinx dx
=∫[0--->π/2] √(sinx)d(sinx)-∫[π/2--->π] √sinx d(sinx)
=(2/3)(sinx)^(3/2) |[0--->π/2] - (2/3)(sinx)^(3/2) |[π/2--->π]
=2/3-(-2/3)
=4/3
=∫[0--->π]√[sinx(1-sin²x)]dx
=∫[0--->π]√[sinxcos²x]dx
=∫[0--->π/2] cosx√(sinx)dx-∫[π/2--->π] cosx√sinx dx
=∫[0--->π/2] √(sinx)d(sinx)-∫[π/2--->π] √sinx d(sinx)
=(2/3)(sinx)^(3/2) |[0--->π/2] - (2/3)(sinx)^(3/2) |[π/2--->π]
=2/3-(-2/3)
=4/3
定积分【0,π^2】sin根号xdx
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